Equation:
C8H18
+
O2
CO2
+
H2O
Balancing:
2 C8H18
+
25 O2
16 CO2
+
18 H2O
Stoichiometry (n or V):
2
:
25
:
16
:
18
Before reaction:
0.025 L
0.600 L
0
0
V octane required to react with 0.600 L oxygen = {2/25}{0.600 L} = 0.048 L, more than available, so octane limits;
O2 = 0.600 - (25/2)(0.025) = 0.600-0.3125 = 0.288 L,
From V octane can then find V CO2 = (16/2)(0.025) = 0.200 L and V H2O = (18/2)(0.025) = 0.225 L
After reaction:
0 L
0.288 L
0.200 L
0.225 L
© R A Paselk
Last modified 2 March 2015