Solutions: a solution occurs when one chemical is completely dissolved or dispersed in another. We most commonly think of solutions as being liquid, but solid solutions also occur, such as the various metal alloys like steel, brass and bronze.
In a solution the substance present in highest concentration is considered to be the solvent, while components in lesser amounts are considered to be solutes. If you dissolve a sugar cube in water you get a sugar solution, where water is the solvent, and sugar is the solute.
FYI
Example: |
The most commonly used concentration term in chemistry = moles of solute dissolved in 1 L of solution.
Making molar solutions.
FYIExample: Make up a 1.00000 L solution of 0.25 M NaCl (note that water is the "default" solvent).
Example: What is the concentration of a solution made by dissolving 10.00 g of KI in enough water to make
|
Dilution problems (see Lecture 12, 14 February).
Example: What is the mole fraction of a solution of 10.0 moles of glycerol dissolved in 15.0 moles of water?
(10 mol) / (10 mol + 15 mol) = 10/25 = 0.400
Colligative properties (properties which depend only on the number or concentration, not on the type, of particles). [Exchange across surfaces model]
Colligative properties are only strictly followed for ideal solutions. That is, other forces are at work in real solutions, so will get deviations. As a result colligative properties are followed most closely for dilute solutions (e.g. <0.1 M) where solute-solute interactions are minimal.
Be able to solve problems for:
Raoult's Law: P = XP°, where P = vapor pressure of substance in solution, P° = the vapor pressure of the pure substance and X = its mole fraction. Recall that mole fraction is the number of moles of substance divided by the total number of moles of all substances in the solution (moles solute/(moles solute + moles solvent)) In other words the vapor pressure of a substance in solution is proportional to the molecular fraction or molecular percentage of that substance in the solution.
Example: What is the vapor pressure of water in 80 proof alcohol (XH2O = 0.79) at 25° C (vapor pressure = 23.76 mmHg).
P = XP°
X = [60g/18.01 g/mol] / [60g/18.01 g/mol + 40g/(2x12.01 + 6x1.008 + 16.00)g/mol
Tb = kbm, where m = molality = moles solute/kg solvent, and kb is a constant specific to the solvent.
Which of the following solutions will have the highest boiling point: 3 m glucose or 1 m aluminum chloride?
First need to look at concentration of particles.
glucose is covalent, so 1 m particles,
aluminum chloride is ionic with 1 mole aluminum ions and 3 moles of chlroide ions for each mole of AlCl3 = 4 m particles,
Therefore the 1 m aluminum choride solution will have the higher bp.
Tf = -kfm, where m = molality = moles solute/kg solvent, and kf is a constant specific to the solvent.
Which of the following solutions will have the lowest melting point: 2 m sugar (sucrose) or 0.8 m calcium chloride?
First need to look at concentration of particles.
sugar is covalent, so 2 m particles,
calcium chloride is ionic with 1 mole calcium ions and 3 moles of chloride ions for each mole of CaCl2 = 2.4 m particles,
Therefore the 0.8 m calcium chloride solution will have the higher bp.
| Syllabus / Schedule |
© R A Paselk
Last modified 15 April 2011