| Chem 107 |
|
Fall 2009 |
| Lecture Notes: Equation Balancing |
|
|
|
|
||
|
|
Example. Balance the following equation as it occurs in acid solution:
MnO4- + Cl- Mn2+ + Cl2
First break the equation into two half reactions, one for Mn and one for Cl
MnO4-
Mn2+
MnO4- Mn2+
MnO4- Mn2+ + 4 H2O
8 H+ + MnO4- Mn2+ + 4 H2O
5 e- + 8 H+ + MnO4- Mn2+ + 4 H2O
10 e- + 16 H+ + 2 MnO8- 2 Mn2+ + 8 H2O
Cl-
Cl2
2 Cl- Cl2
2 Cl- Cl2
2 Cl- Cl2
2 Cl- Cl2 + 2 e-
10 Cl- 5 Cl2 + 10 e-
10 e- + 16 H+ + 2 MnO4- + 10 Cl- 2 Mn2+ + 8 H2O + 5 Cl2 + 10 e-
Redox Balancing - Example in Basic Solution
ClO2 ClO2- + ClO3-
First break the equation into two half reactions, one for Mn and one for Cl
ClO2
ClO2-
1 e- + ClO2 ClO2-
This one is easy - just one step: balance charge with an electron.
ClO2
ClO3-
H2O + ClO2 ClO3-
2 OH- + H2O + ClO2 ClO3- + 2 H2O
2 OH- + H2O + ClO2 ClO3- + 2 H2O + 1 e-
1 e- + ClO2 + 2 OH- + H2O + ClO2 ClO2- + ClO3- + 2 H2O + 1 e-
Cancelling and gathering terms:
|
|
© R A Paselk
Last modified 25 October 2005